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OpenStudy (anonymous):
\[x ^{\frac{ 1 }{ 4}}\]
OpenStudy (anonymous):
would it just be the fourth root of x
OpenStudy (jack1):
yep
OpenStudy (anonymous):
thank you!
OpenStudy (jack1):
welcome, it was all u hey ;D
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OpenStudy (anonymous):
\[n ^{\frac{ 4 }{ 3}}= \sqrt[3]{n}^{4}\] right?
OpenStudy (jack1):
yes, if that's just (n^4) and not whole thing ^4
OpenStudy (anonymous):
yep
OpenStudy (jack1):
cools, then perfect!
OpenStudy (anonymous):
now here is the tough one...
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OpenStudy (anonymous):
\[(p ^{\frac{ 7 }{ 4 }})^{\frac{ 1 }{2 }}\]
OpenStudy (jack1):
that's really small on my screen, is that 7/4 and 1/2 ?
OpenStudy (anonymous):
yes it is
OpenStudy (jack1):
cool, so just multiply out the brackets first, then do what you were doing
remember the rules:
\[x^4 \times x^3 = x^{4+3} = x^7\]
but if its
\[(x^4)^3 = x^{4 \times 3} = x^{12}\]
OpenStudy (jack1):
so ours is
\[(x^{7/4})^{1/2} = x^{7/4 \times 1/2} = x^{7/8}\]
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OpenStudy (jack1):
so now that you're rid of the brackets
\[x^{7/8} = \sqrt[8]{x^7}\]