Question

a firefighter jumps out the window into a net.if the window is 25m above the net, a) at what velocity does the fighter hit the net? b) how long will it take the firefighter to hit the west?

Answer 1

well, the acceleration would be -9.8 m/s^2 do to gravity.

Answer 2

what is the given ? i need formula? thank u for helping me ...

Answer 3

please help me ???? i need the equation ??? thank u

Answer 4

1) y=4(x+1)*2 ,2) y=-5(x-2)*2+15, 3)y=-2(+2)*2-1, 4) y=3(x-6)*2-11,5) y=(x-10)*2-25, transform the ff functions in the form y=ax*2+bx+c

Answer 5

v^2=u^2+2*a*s u=initial vel=0 v final vel a =g s=25
v=sqrt2*9.8*25
v=u+a*t u=0 a=g t=v/g

Answer 6

i dont understand can u explain to me ??? sorry

Answer 7

You probably want to take this to the physics section.

Answer 8

please more explanation in physics please.....

Answer 9

Vf^2 = Vi^2 + 2ad ; final velocity = Vf, initial velocity is Vi, a = acceleration, d = displacement
Because he is just free falling out of a window, his Vi is 0
His displacement is 25 m because he's 25m about the net.
Acceleration is constant -9.8 m/s^2

Plug in the components to figure out Vf.

Then using Vf = Vi + at
plug in Vf, Vi, and a to figure out how long it takes.