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Mathematics 20 Online
OpenStudy (lifeisadangerousgame):

Okay I still don't really understand how to do this..

OpenStudy (lifeisadangerousgame):

OpenStudy (lifeisadangerousgame):

f(x) = 2x^2 + 5 and g(x) = -3x

OpenStudy (cwtan):

\(\Huge 2 \times f [g (x)]\)

OpenStudy (lifeisadangerousgame):

what I got is 2(2x^2 + 5)(-3x)

OpenStudy (cwtan):

\(\Huge 2 \times f[value-of-g(-1)]\)

OpenStudy (cwtan):

f(x)= ........ f(-1)= substitute -1 into x fg(x)= f[g(x)]= substitute value of g(x)

OpenStudy (lifeisadangerousgame):

I don't understand what you just did :/

OpenStudy (cwtan):

example: f(x)=2x g(x)=3x fg(2)=f[g(2)]= f[ 3x2]=6x2=12

OpenStudy (lifeisadangerousgame):

still don't understand that I'm sorry

OpenStudy (lifeisadangerousgame):

Okay I'm going to try to do the problem then maybe you could check me

OpenStudy (cwtan):

ok f(x)= 2x how do u find the value of f(1)

OpenStudy (cwtan):

P/s: rmb the bracket in function isnt meant for multiply

OpenStudy (lifeisadangerousgame):

2(2x^2 + 5)(-3x) 2(-6x^3 - 15x) -12x^3 - 30x -12(-1)^3 - 30(-1) 12 + 30 = 42

OpenStudy (cwtan):

Wrong.

OpenStudy (lifeisadangerousgame):

That's what someone else got when they did it :/

OpenStudy (cwtan):

1st step should be 2[2(-3x)^2+5]

OpenStudy (cwtan):

when f(x)= 2x you substitute x=1 to find f(1)=2 -------------------------------- so when fg(x) its = f[g(x)] where g(x) is a value after u substitute -1 into the function and then u take the value after u solve for g(x) substitute into the function f(x)

OpenStudy (cwtan):

Let g(x)=y fg(x)= f[g(x)]= f(y)

OpenStudy (lifeisadangerousgame):

I don't understand when you make it all f(g)(f) terms and stuff, it goes right over my head :/

OpenStudy (cwtan):

fg(x) = f[ g(x) ] remember this then assume g(x) is a number A NUMBER! so after u find the number that represent g(x) go substitute into f(x)

OpenStudy (cwtan):

if u stl not understand, bump this question. i tried my best to guide you but failed.

OpenStudy (lifeisadangerousgame):

Okay, thank you anyway!

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