Okay I still don't really understand how to do this..
f(x) = 2x^2 + 5 and g(x) = -3x
\(\Huge 2 \times f [g (x)]\)
what I got is 2(2x^2 + 5)(-3x)
\(\Huge 2 \times f[value-of-g(-1)]\)
f(x)= ........ f(-1)= substitute -1 into x fg(x)= f[g(x)]= substitute value of g(x)
I don't understand what you just did :/
example: f(x)=2x g(x)=3x fg(2)=f[g(2)]= f[ 3x2]=6x2=12
still don't understand that I'm sorry
Okay I'm going to try to do the problem then maybe you could check me
ok f(x)= 2x how do u find the value of f(1)
P/s: rmb the bracket in function isnt meant for multiply
2(2x^2 + 5)(-3x) 2(-6x^3 - 15x) -12x^3 - 30x -12(-1)^3 - 30(-1) 12 + 30 = 42
Wrong.
That's what someone else got when they did it :/
1st step should be 2[2(-3x)^2+5]
when f(x)= 2x you substitute x=1 to find f(1)=2 -------------------------------- so when fg(x) its = f[g(x)] where g(x) is a value after u substitute -1 into the function and then u take the value after u solve for g(x) substitute into the function f(x)
Let g(x)=y fg(x)= f[g(x)]= f(y)
I don't understand when you make it all f(g)(f) terms and stuff, it goes right over my head :/
fg(x) = f[ g(x) ] remember this then assume g(x) is a number A NUMBER! so after u find the number that represent g(x) go substitute into f(x)
if u stl not understand, bump this question. i tried my best to guide you but failed.
Okay, thank you anyway!
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