Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

find the first derivative y=(csc x + cot)(csc x - cot)

OpenStudy (anonymous):

Do you know the product rule?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Do you know the derivatives of those trig functions? :)

OpenStudy (anonymous):

no

OpenStudy (anonymous):

The derivative this time is 0

OpenStudy (anonymous):

y = (csc x + cot x)(csc x - cot x) = (csc x)^2 - (cotx)^2 = 1 + (cotx)^2 - (cotx)^2 =1 And the derivative of 1 is 0

OpenStudy (anonymous):

Maybe he'd like to know how to do it instead of just being given the answer?

OpenStudy (anonymous):

how you get the power to the 2 for csc x and cot x?

OpenStudy (anonymous):

By simplifying the expression, multiplying what's inside the parenthesis

OpenStudy (anonymous):

so i have to use foil?

OpenStudy (anonymous):

Yep, use the foil method

OpenStudy (anonymous):

ok. i dont understand the csc and cot like what do they equal to?

OpenStudy (anonymous):

What do you mean by that? Do you mean what they equal after you multiply them?

OpenStudy (anonymous):

like sin x= cos x and cos x = -sinx or tan x= sin x/cos x

OpenStudy (anonymous):

csc x = 1/sin x and tan = 1/tan x

OpenStudy (anonymous):

No no no! The derivative of csc x is -cosxcotx and the derivative of tan x is sec^2 x. While yes, you can foil this before you find the derivative, you don't have to.

OpenStudy (anonymous):

Oh, I got confused for a second there...oops ^^*

OpenStudy (anonymous):

Becki is right, but using foil just simplifies the expression to cut back on confusion

OpenStudy (anonymous):

so csc x = -cosx cot x and tan x = sec^2? What about sin and cos?

OpenStudy (anonymous):

sin x and cos x you had correct. the deriviatives of each of those is cos x and -sin x respectively.

OpenStudy (anonymous):

so they equal to each other?

OpenStudy (anonymous):

No. When you differentiate sin x, you get cos x. When you differentiate cos x, you get -sin x.

OpenStudy (anonymous):

oooh ok but what about dividing cos x and sin x?

OpenStudy (anonymous):

Dividing them by what?

OpenStudy (anonymous):

cos x / sin x

OpenStudy (anonymous):

That's the definition of cot x.

OpenStudy (anonymous):

i though it equal to tan x

OpenStudy (anonymous):

Here's what i got for your original question. I went ahead and foiled it since you probably already did that. Then I used the chain rule to differentiate.

OpenStudy (anonymous):

how you get (2cot x)? i though the 2 supposed to be on the outside of the parentheses

OpenStudy (anonymous):

never mind

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!