Does anyone know how to solve backwards? Write a trigonometric equation with solutions 5pi/6 and 7pi/6. Check by solving your equation.
you have to look at your unit circle for that. I suggest that for future studies you memorize the thing since precal is pretty much all about that. i'll explain.
use the unit circle and the law of sin and cosine. Yes, and like Aero_Exis writes MEMORIZE IT!
on your unit circle you can see where 5pi/6 and 7pi/6 are in quadrant 2 and 3
so basically you have the cos or sin that can equal those two values in those two quadrants.
you may use either one. the cos(-sqrt3/2) can get you to 5pi/6
as shown on the unit circle. and in effect that equation also gets you 7pi/6 as well because sqrt3/2 is negative in two areas on the unit circle
at 150 degrees and at 210
I did 3tan(x)^2 - 1=0
i can say that you won't see anything to the power of 2 in the unit circle
trig((5pi/6-x)(7pi/6-x)) = trig(0)
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