Question

factoring for
n^2 - 15n + 56 i was thinking n - 8 and n -7

Answer 1

(n-8)(n-7)
You are correct.

Answer 2

what about for q^2 - 8q + 12 i was thing
( q-4 ) (q-3)
but also maybe (q-2) (q-6)

Answer 3

thinking*

Answer 4

It is (q-2)(q-6).
Not sure if I can explain factoring to you in my own terms but this is because -4 - 3 does not equal 8.
-2 - 6 = -8
Which satisfies the original equation.

Answer 5

does not equal negative 8 ***

Answer 6

thank you i understand :)

Answer 7

You can always check your answers by multiplying across.
(q-2)(q-6)
q*q = q^2
q * -6 = -6q
-2 * q = -2q
-2*-6 = 12

= q^2 - 6q - 2q + 12
= q^2 - 8q + 12