Use l'Hopital's rule to evaluate the one-sided limits. Support your answer graphically. The limit as x approaches 0 from the left of sinx/x^3.
you know what L'Hopital's rule is ?
Yes, how would I use it in this case?
whats the derivative of numerator ? whats the derivative of denominator ?
Cosx/ 3x^2
correct! now tell me whether you can use L'Hopital again ??
I cannot now b/c its it's some number over 0. I just don't know which infinity it is and why.
ok! the hint is in x approaches 0 from the "left" you know what that means ? x>0 or x <0 ?
X<0?
correct! since x< 0 the denominator , obviously is positive, right ? (x^2 always positive) what about the numerator ?
The numerator is negative
really ? when is cos x negative and positive ?
Oh I see, cosx is positive on the right side of the unit circle, meaning that the answer is positive infinity. Thanks so much!
absolutely correct! cos is positive in 1st and 4th quadrant, so numerator also positive :)
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