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Mathematics 20 Online
OpenStudy (anonymous):

differentiate sqrtx

OpenStudy (anonymous):

i got (1/2)sqrtx

terenzreignz (terenzreignz):

The power rule \[\Large \frac{d}{dx}x^n=nx^{n-1}\] applies even in the most jarring of exponents (for as long as they are constant)

OpenStudy (anonymous):

so i am right

terenzreignz (terenzreignz):

Keep that, and the fact that \[\Large \sqrt x = x^{\frac12}\] in mind and the answer will be clear ^_^

OpenStudy (vjordillo):

1/2sqrtx

OpenStudy (anonymous):

\[\sqrt{x}/2\]

OpenStudy (anonymous):

or would it be -sqrtx/2

terenzreignz (terenzreignz):

That's not it :) From the power rule, you should get \[\Large \frac{d}{dx}\sqrt x = \frac{d}{dx}x^{\frac12}=\frac12x^{-\frac12} \] And just simplify

OpenStudy (anonymous):

so it would be (1/2)(1/sqrtx)

terenzreignz (terenzreignz):

Yes, or simply put, \[\Large \frac1{2\sqrt x}\] as @vjordillo has put it.

OpenStudy (anonymous):

ok

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