Question

what do i have to do to find the mole ratio of this?

Answer 1

\[Na _{2}S _{2}O _{3}*5H _{2}O \to N _{2}S _{2}O _{3}\]
given that the first part (sodium thiosulfate) weighs 6.195 g

Answer 2

u want to find mole ratio of those two compounds ?

Answer 3

yes

Answer 4

find the molar mass of those compounds

Answer 5

???? can you do that ?

Answer 6

yes. for the first one i got 184 g

Answer 7

is that correct?

Answer 8

and for second one ?

Answer 9

and Na2S2O3= 158 g

Answer 10

is the first one correct?
i wasnt sure if the 5H2O is one or ten oxygens..

Answer 11

5H2O is 10 h and 5 O

Answer 12

ok so then the correct molar mass of the first one would be 248g

Answer 13

and there is .025 mol of Na2S2O3*H2O

Answer 14

how do i go about the finding of the molar ratio now?

Answer 15

moles = gram / molar mass

Answer 16

yes

Answer 17

if first part contains the 6.195 gram then second part contains? u find out
as u know 248 gram of first part contains the 158 gram of second part :)
so the 6.195 gram of first part contains = 158*6.195 /248=

Answer 18

so basically i set up this eqaution
\[x=\frac{ 6.193*158 }{ 248 }=3.946\]

Answer 19

and this is also .025 mol. so mole ratio is is 1:1 :)

Answer 20

so for future reference could this have been done just from the coefficients or is that incorrect?

Answer 21

just for saving time and such