Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (psymon):

Prove if A is a subset of B iff B compliment is a subset of A compliment

OpenStudy (shamil98):

1) Assume that A ⊂ B. Choose an element c ∈ B' (B' means complement of B) Proof by contradiction: Assume that c ∉ A' Since c ∉ A' then c ∈ A (that is it is is not an element of A') Then since A ⊂ B, c ∈ B., This is a contradiction of the assumption that c ∈ B'. Therefore c ∈ B' implies that c ∈ A' -------------- 2) This is a corollary (implied result) of (1) Assume that B' ⊂ A' Call B' the subset D. Call A' the subset E Then we are trying to prove that since D ⊂ E, then E' ⊂ D'. But we have already proved this with different letters A and B, so we already know this result. End proof.

OpenStudy (psymon):

\[A \subseteq B \iff B^{C} \subseteq A^{C}\] Basically, I just don't know how to do it in a way that isnt really sloppy or in a way thats convincing..... Are you serious @shamil98?

OpenStudy (shamil98):

What?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!