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Mathematics 13 Online
OpenStudy (watchmath):

What we can say about the point \(x=c\) if \(f'(c)=f''(c)=0\) dan \(f'''(x) >0\) for all \(x\)

OpenStudy (agent0smith):

hmm... That it's an inflection point, at least...

OpenStudy (agent0smith):

Eg \[\Large f(x) = x^5\]\[\Large f \prime (x) = 5x^4\]\[\Large f \prime \prime (x) = 20 x^3 \]\[\Large f \prime \prime \prime (x) = 60x^2\] the fourth derivative is positive for all x. The others are all zero for x=0

OpenStudy (watchmath):

why is that true in general?

OpenStudy (watchmath):

Sorry actually I wanted to say that \(f'''(c)>0\) (so not necessarily \(f'''(x)>0\) for all x

OpenStudy (agent0smith):

Ok so then it seems like we have an inflection point which is on on upward portion of the graph... like the inflection point of say an x^3 graph vs an -x^3 graph

OpenStudy (agent0smith):

I don't think it matters if f''' is > 0 for all x or not... it seems that we just have an inflection point on an upward section of the curve, rather than an inflection point on the downward section of the curve |dw:1381549503654:dw| or maybe in terms of displacement y... y' - velocity would be zero y'' - acceleration would be zero but the rate of change of acceleration y''' is positive, as opposed to negative... so acceleration is increasing not decreasing.

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