Question

Find dy/dx for sin(xy) =√x2 + y2.

Answer 1

to make life simpler, you can first square both sides, and then take the derivative :)

Answer 2

\[
\begin{align*}
\sin^2(xy)&=x^2+y^2\\
2\sin(xy)\left(y+xy'\right)&=2x+2yy'\\
\left(2x\sin(xy)-2y\right)y'&=2x-2y\sin(xy)\\
y'&=\frac{2x\sin(xy)-2y}{2x-2y\sin(xy)}
\end{align*}
\]

Answer 3

xD

Answer 4

shamil ;3

Answer 5

u can't hide from me ԅ(≖‿≖ԅ)

Answer 6

*disappears*

Answer 7

@watchmath check out your last step.

Answer 8

yes, thanks :), it should be the reciprocal of that

Answer 9

:)
@Shawna311