Question

The integer 47 is to be expressed as a sum of n
consecutive positive integers. The value of n could be
which of the following?
I. 2
II. 3
III. 5
(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) I, II, and III

Answer 1

@phi

Answer 2

you can say for 2 consecutive numbers: x+x+1= 47
2x+1= 47
2x=46
x=23

so you can add 23+24 to get 47
I must be one of the choices

Answer 3

so (B) is NOT the answer

Answer 4

well why not try and use the values of n

n = 2

so the integers are n and n + 1

so n + n + 1 = 47
2n + 1 = 47

solve for n.

same process for n = 3

the integers are

n, n+1, n + 2

form an equation and see if it works

n = 5

n, n+1, n +2, n + 3, n + 4

let there sum = 47 and solve for n...

Answer 5

for 3 numbers we could say x-1+x+x+1 = 3x = 47
but 47 is not evenly divisible by 3. so II. is not allowed. (C) and (E) are not the answer

Answer 6

the 5 numbers could be (x-2)+ (x-1) + x + (x+1) + (x+2) = 5x =47
47 is not evenly divisible by 5, so III is out.

Answer 7

so (A)?

Answer 8

yes