Question

Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three, solve for f(g(x)) when x = 2.

Answer 1

Same as the last one, but now g(x)=\[\frac{ x+4 }{ 3 }\], so you have to put that into f(x), solve the expression, and replace x with 2

Answer 2

Is it 2 then?

Answer 3

So f(g(x)) = ((x+4)/3)^2+2((x+4)/3) + 3

Answer 4

and when x = 2, that should give (6/3)^2+2(6)+3

Answer 5

So unfortunately the answer isn't 2

Answer 6

Well when I answer it like that I get 19 and thats not one of the possible answers..

Answer 7

Can you show me your working out? Because if you continue from the equation \[(6/3)^2+2*6+3\]
then your answer shouldn't be 19

Answer 8

remember PEMDAS

Answer 9

Whenever f(g(x)) is asked for a specific value of x, say x = 2, the easier approach is to find g(2) first and then put that value for x in f(x).

Answer 10

Well I did the (6/3) and got 2 then I raised that to the second power and got 4. Then I multiplied 2 by 6 got 12 and added that to the 4 so I got 16 and then finally I added 3... So thats how I got 19.

Answer 11

Oh damn you are right, I miscalculated :P

Answer 12

The correct equation should be \[(6/3)^2+2*2+3\]

Answer 13

Which should give 11

Answer 14

Yup thats what I got now. And this one is a possibility! YAY!

Answer 15

Great :D

Answer 16

g(x) = (x+4)/3
g(2) = 6/3 = 2
f(x) = x^2 + 2x + 3
f(g(2)) = f(2) = 2^2 + 2(2) + 3 = 11

Answer 17

Thank you!

Answer 18

Don't sweat it