Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

LET a,b belong to R SHOW that if a

OpenStudy (watchmath):

Argue by contradiction. Suppose a > b. What would happen if we assume that?

OpenStudy (anonymous):

that means a> b + 1/n

OpenStudy (watchmath):

why?

OpenStudy (anonymous):

no!! sorry it will be na>b that lead to a>b/n then b/n>a

OpenStudy (watchmath):

Does it lead to any contradiction?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

no what I wrote it does not lead but I wrote like if I use the property

OpenStudy (anonymous):

are you with me?

OpenStudy (watchmath):

We want to get a contradiction to the given statement. A contradiction to that statement means that there is an integer m such that a> b + 1/m . How can we get such m ?

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

I DO NOT KNOW I want to know that please

OpenStudy (watchmath):

well we need to work backward. Suppose there is such m such that a > b+ (1/m). Then a-b > 1/m. Then m > 1/(b-a). How the archimedean property fit in this situation?

OpenStudy (watchmath):

m > 1/(a-b) I meant

OpenStudy (anonymous):

we will say m+b>a

OpenStudy (anonymous):

no!!1

OpenStudy (anonymous):

one min

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!