Question

A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side lengths equal to 16.35 in. Find the area of the second octagon.
A. 461.60 in2
B. 882.9 in2
C. 717.06 in2
D. 642.66 in2

Answer 1

2 octagons
1st has a side length of 10.9 in
2nd has side length of 16.35 in

Area of the 1st one is 392.4 square inches
2nd one... dunno

but we can use the ratios for their correspondent components, that is, the sides and the Areas

\(\bf \cfrac{Area1}{Area2} = \cfrac{side1^2}{side2^2}\qquad thus\\ \quad \\
\cfrac{392.4}{x} = \cfrac{10.9^2}{16.35^2}\)

solve for "x"

Answer 2

882.9in^2 (: ty

Answer 3

yw