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Mathematics 22 Online
OpenStudy (anonymous):

how to I put this in the quadratic equation? (x)^2 / (2-x)^2

OpenStudy (anonymous):

you foil out the (2-x)^2 which will give you x^2-4x+4

OpenStudy (jdoe0001):

hmmm that wouldn't work in the quadratic formula

OpenStudy (tkhunny):

You don't. Do you seen one of these? "="

OpenStudy (anonymous):

you can put an expression into the quadratic equation

OpenStudy (anonymous):

but no you do not put this expression into the quadratic formula... what is the actual question? simplify or what?

OpenStudy (anonymous):

I was trying to solve for x.

OpenStudy (jdoe0001):

hmm what's the original material? or what's the context?

OpenStudy (anonymous):

It's a chemistry question Initially, only A and B are present, each at 2.00 M. What is the final concentration of A once equilibrium is reached? The reversible chemical reaction A+B⇌C+D has the following equilibrium constant: Kc=[C][D]/[A][B]=5.0

OpenStudy (anonymous):

(x)^2 / (2-x)^2 = 5.0

OpenStudy (anonymous):

ehuman that is incorrect you can't cancel out the (2-x)^2

OpenStudy (anonymous):

IF the equation is equal to 0, you can multiply both sides by (2-x)^2 and bobs your uncle it sure does cancel out.

OpenStudy (anonymous):

but it wasn't given as an equation it was given as an expression and now you can multiply the (4x^2-4x+4) with 5 and you get x^2=5x^2-20x+20 which you can simplify out to 4x^2-20x+20 which you can put into the quadratic formula

OpenStudy (anonymous):

I see. Thank you so much!

OpenStudy (anonymous):

not a problem

OpenStudy (anonymous):

he posted the missing info while I was posting that, and I did say he was missing info, and that IF he was set to zero, then my explanation was true. I was being a smarty because I knew he didnt provide enough info at that point to solve it.

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