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A volume of 115\({\rm mL}\) of \(\rm H_2O\) is initially at room temperature (22.0\(\rm{}~^{\circ}C\)). A chilled steel rod at 2.00\(\rm~^{\circ}C\) is placed in the water. If the final temperature of the system is 21.4\({\rm ~^{\circ}C}\) , what is the mass of the steel bar? Use the following values: specific heat of water = 4.18 \(\rm J/(g\cdot{^{\circ}C})\) specific heat of steel = 0.452 \(\rm J/(g\cdot{^{\circ}C})\)
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