Question

y=sqrt(x), find dy/dt when x=4, given dx/dt=3.

Answer 1

http://www.youtube.com/watch?v=ywEqxpgxark

Answer 2

keep in mind that \(\large \bf \sqrt{x}\implies x^{\frac{1}{2}}\)

Answer 3

Can someone explain this to me step by step?

Answer 4

utube linlk

Answer 5

link*

Answer 6

its similar

Answer 7

Ok let's start with this:
\[\Large \frac{dy}{dx}\quad=\quad \frac{\left(dy/dt\right)}{\left(dx/dt\right)}\]

Answer 8

@UchihaMadara I see.

Answer 9

could i get a medal

Answer 10

Given a function y, we should be able to find dy/dx without too much trouble.
Then plug in dy/dx evaluated at x=4, and plug in dx/dt.
Andddd move some stuff around to solve for dy/dt.

Answer 11

could i get a medal

Answer 12

\[y=x ^\frac{ 1 }{2 },\frac{ dy }{dt }=\frac{ 1 }{2 }x ^{\frac{ -1 }{ 2 }}\frac{ dx }{ dt }\]
\[when x=4,\frac{ dx }{ dt }=3\]
\[\frac{ dy }{ dt }=\frac{ 1 }{2 }\left( 4 \right)^{\frac{ -1 }{2 }}*3=\frac{ 3 }{2*2 }=\frac{ 3 }{4 }\]