Question

create a colored in, closed figure on a coordinate plane (graph) and then state the inequalities that allow you to create the figure. 1.The graph –– a coordinate plane with a colored in, closed figure. Each segment must be labeled. 2.The inequalities –– show the work for finding the inequality that defines each segment. 3.Your reflection –– write a paragraph, of 3 or more sentences, as you reflect on this activity and your final product. You may use specific questions to guide your thoughts, if needed.

Answer 1

what is it? graph theory with chromatic numbers?

Answer 2

you will create a colored in, closed figure on a coordinate plane and then state the inequalities that allow you to create the figure.

Answer 3

Algebra inequalities

Answer 4

Ok np thanks

Answer 5

I am sorry, wonder where are mathematicians? @jdoe0001

Answer 6

http://www.regentsprep.org/regents/math/algebra/ae85/grineqa.htm

make a quickie linear shape, then color it, then use the delineations to get the lines, and the colored area to get the inequality

Answer 7

Thanks
You

Answer 8

like so, 3 lines, each have an equation, each have a shaded region
and the COLORED shape will be the intersection of all 3 SHADED regions

Answer 9

How do I wright an inequality for each Sid of the triangle

Answer 10

I'll show you ... say 1 one of those lines

my slope will be 2/3,
using the point-slope form, so \(\bf \textit{say using point } (0,2)\\ \quad \\
y-y_1=m(x-x_1)\implies y-2=\cfrac{2}{3}(x-0)\implies y = \cfrac{2}{3}x+2\)

Answer 11

now I pick a point in the shaded area for it... say .... point (2 ,3 ) is in the shaded or TRUE Area for that line, so
\(\bf 3 \square \cfrac{2}{3}(2)+2\implies 3 \square \cfrac{4}{3}+12\implies 3 \square\cfrac{40}{3}\implies 3 \square 13\cfrac{1}{3}\\ \quad \\

\textit{so obviously, }\quad 13\cfrac{1}{3}\quad \textit{ is bigger than }\quad 3\quad \textit{so my inequality will be}\\ \quad \\
3 < 13\cfrac{1}{3}\)

Answer 12

so my inequality equation will end up as \(\bf y < \cfrac{2}{3}x+2\)

Answer 13

and you'd do the same for the other lines

Answer 14

Thank you so much man