Mathematics
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OpenStudy (anonymous):
Make x the subject
y = (2x-1)/(x+3)
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OpenStudy (anonymous):
\[y=\frac{ 2x-1 }{x+3 }\]
OpenStudy (anonymous):
X= -10,-4,-2,4
Y=3,9,-5,1
OpenStudy (phi):
as a first step, multiply both sides by (x+3) like this:
\[ y\cdot (x+3)=\frac{ 2x-1 }{x+3 } \cdot (x+3) \]
OpenStudy (anonymous):
Yes I've done that but I don't know to how continue ...
OpenStudy (phi):
what do you get after simplifying the right side ?
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OpenStudy (anonymous):
I solved for x and y, they have more than one solution.
OpenStudy (anonymous):
y(x+3)=2x-1
OpenStudy (anonymous):
make xs in one side and ys the otherside
OpenStudy (anonymous):
We're making x the subject not solving...
OpenStudy (phi):
now distribute the y : multiply each term in the parens by y
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OpenStudy (anonymous):
yx + 3y = 2x-1
OpenStudy (phi):
I would add -yx to both sides
and add +1 to both sides
OpenStudy (anonymous):
3y+1=2x-yx?
OpenStudy (phi):
almost done... factor out the x from each term on the right side
OpenStudy (phi):
factoring x out is the opposite of "distributing"
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OpenStudy (anonymous):
3y+1=x(2-y)
x=(3y+1)/(2-y)
OpenStudy (phi):
yes
OpenStudy (anonymous):
Thank you for your help!
OpenStudy (phi):
yw