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Mathematics 20 Online
OpenStudy (anonymous):

Algebra 2 stuff

OpenStudy (anonymous):

@shamil98 Let's have fun?

OpenStudy (anonymous):

Do you know summation notation? \[ \sum_{k=0}^{n} a_k \]

OpenStudy (shamil98):

No, not really. Explain?

OpenStudy (anonymous):

Okay. Do you know what a function is?

OpenStudy (shamil98):

Yes.

OpenStudy (anonymous):

Okay do you know what a sequence is?

OpenStudy (shamil98):

Nope.

OpenStudy (anonymous):

A sequence is a type of function, but the input must be a natural number

OpenStudy (anonymous):

Natural numbers are numbers \(1, 2, 3, 4,...\)

OpenStudy (anonymous):

So for example, a function lets you do \(f(2.5)\), but a sequence won't allow \(2.5\) as an input.

OpenStudy (anonymous):

Functions are generally written like \(f(x)\) where \(x\) is the input. Sequences are usually written as \(a_n\) where \(n\) is the input. So \(a_1\) is to \(f(1)\) as \(a_n\) is to \(f(x)\).

OpenStudy (anonymous):

This is just a definition, not a complicated concept or anything. Sequence is just a name of a certain type of function.

OpenStudy (anonymous):

Now \[ \sum a_n \]just takes a sum of a sequence. I'll start off with very simple example.

OpenStudy (shamil98):

Oh, I've done some sequences before like finding the 10th sum of \[a _{n}=n+5\] or something

OpenStudy (anonymous):

We could let \(a_n=n^2\)

OpenStudy (anonymous):

\[ \sum_{n=1}^3 n^2 = (1)^2+(2)^2+(3)^2 \]

OpenStudy (shamil98):

The top 3 and bottom n =1 they represent the terms in which you substitute n right?

OpenStudy (anonymous):

At the bottom when you say \(n=1\) you are specifying that \(n\) is the input variable and where the sum starts. Now at the top the \(3\) is where it ends.

OpenStudy (shamil98):

Got it .

OpenStudy (anonymous):

There are certain sums which it is important to know.

OpenStudy (anonymous):

\[ \sum_{i=1}^ni=\frac{n(n+1)}{2} \]

OpenStudy (shamil98):

I've seen that formula before, when I was studying for the SAT..

OpenStudy (anonymous):

\[ \sum_{i=1}^nc=\underbrace{c+c+c+\ldots +c}_n = nc \]

OpenStudy (anonymous):

\[ \sum_{i=1}^nca_i = c\sum_{i=1}^na_i \]You can pull out constants... \[ \sum_{i=1}^n(a_i+b_i) = \sum_{i=1}^na_i+ \sum_{i=1}^nb_i \]You can sum over particular terms.

OpenStudy (anonymous):

In algebra 2 you learn about two special types of series: Arithmetic series. They come in the form: \[ a_n=a_1+(n-1)d \]Where \(d\) is the difference between any two consecutive terms. Geometric series. \[ a_n=a_1r^{n-1} \]Where \(r\) is the ratio between two consecutive terms.

OpenStudy (anonymous):

I don't necessarily want you to memorize it. To understand it a bit and forget it later is fine. Knowing this, though, can help you help others on this site.

OpenStudy (shamil98):

Thanks, I'll try and memorize it though, the more the knowledge the better :D

OpenStudy (anonymous):

\[ \sum_{i=1}^n a_i=\frac 12n (a_n+a_1) \]When \(a_i\) is an arithmetic series. \[ \sum_{i=1}^na_i=a_1\frac{1-r^n}{1-r} \]When \(a_i\) is a geometric series.

OpenStudy (anonymous):

Oh, by the way "series" is just a word for a sum of a sequence.

OpenStudy (anonymous):

This is a pretty quick overview of what goes on with sequences in algebra 2.

OpenStudy (anonymous):

@shamil98 Would you like a test question?

OpenStudy (shamil98):

Sure.

OpenStudy (anonymous):

What is the sum of all numbers divisible by 8 from 1 to 1000.

OpenStudy (shamil98):

hmm..

OpenStudy (anonymous):

Our sequence is \[ 8,16,24,\ldots,1000 \]

OpenStudy (anonymous):

Arithmetic or geometric?

OpenStudy (shamil98):

The first number greater than 1 divisible by 8 is 8,16,24,32,36 and so on..

OpenStudy (shamil98):

numbers*

OpenStudy (anonymous):

@shamil98 What is the formula for this sequence?

OpenStudy (anonymous):

\(a_1=8\).\[ a_n=a_1+(n-1)d \]You gotta find \(d\).

OpenStudy (anonymous):

arithmetic btw

OpenStudy (anonymous):

(You technically don't need the formula but for exercise let's get it).

OpenStudy (shamil98):

gah, im confused .. 1000/8 = 125 so 1000 is the largest possible number that can be divided by 8..

OpenStudy (shamil98):

and the smallest one is 8.

OpenStudy (anonymous):

Use the formula wio gave you

OpenStudy (shamil98):

an = 8 + (n-1)d

OpenStudy (anonymous):

What's an? :D

OpenStudy (anonymous):

in this case

OpenStudy (anonymous):

@shamil98 Try using `\[a_n=...\]` \[ a_n=\ldots \]

OpenStudy (shamil98):

wait i know this.. s = 1/2 (1st term + last term) (last term) right?..

OpenStudy (anonymous):

You should really start of with questions like... determine whether the following sequences are arithmetic or geometric.

OpenStudy (anonymous):

\[S_n=\frac 12 n (a_1+a_n) \]But I already wrote that above.

OpenStudy (anonymous):

We don't need to give shamil kiddy questions

OpenStudy (anonymous):

Eh best to start of with the basics then get into all the notation etc.

OpenStudy (shamil98):

s = 124/2 (8+1000) s = 62496?..

OpenStudy (anonymous):

Why 124?

OpenStudy (shamil98):

8*1 = 8 8*125 = 1000 125 - 1 = 124 am i wrong?..

OpenStudy (anonymous):

There are 125 numbers between 1 and 125.

OpenStudy (anonymous):

By the way, the explicit formula in this case is: \[ a_n=8+(n-1)8 = 8n \]

OpenStudy (shamil98):

a_n = 8 + (125-1)(8) then?.

OpenStudy (shamil98):

Wio, am i right or wrong bout the sum tho? o.o

OpenStudy (anonymous):

\[ a_{125}=8+((125)-1)(8) \]

OpenStudy (anonymous):

Since \(a_n\) is a sequence of \(n\), we don't need to substitute \(125\) into it.

OpenStudy (anonymous):

You would be correct about the sum if you used \(n=125\)

OpenStudy (shamil98):

so, s = 125/2(8+1000) s= 63000

OpenStudy (anonymous):

That is right.

OpenStudy (anonymous):

Okay, want a quick and easy geometric one?

OpenStudy (shamil98):

Sure

OpenStudy (anonymous):

A man is given 1 grain of rice on the first day. Each day he is given twice the number he was given the previous day. How many grains is he given by the 64th day?

OpenStudy (shamil98):

1 = 1 2 =2 3 = 4 4= 8 5 = 16 and so on..

OpenStudy (anonymous):

Yes.

OpenStudy (shamil98):

S = (first term)(1-r^n)/(1-r)

OpenStudy (shamil98):

Although I am bit curious what would r represent in this formula?

OpenStudy (anonymous):

ratio between two consecutive terms.

OpenStudy (shamil98):

so the ratio in this case is 1/2 right?

OpenStudy (anonymous):

No, it is 2

OpenStudy (shamil98):

oh.

OpenStudy (shamil98):

2^n -1

OpenStudy (shamil98):

n represents the number of days ? correct?..

OpenStudy (anonymous):

yeah

OpenStudy (shamil98):

so 2^64 - 1?

OpenStudy (shamil98):

18446744073709551615 is your answer o.o

OpenStudy (anonymous):

yeah that looks right.

OpenStudy (anonymous):

nice number looool

OpenStudy (anonymous):

How many pounds of rice?

OpenStudy (shamil98):

18446744073709551615 pounds of rice :D

OpenStudy (shamil98):

that's a lot of rice man.

OpenStudy (anonymous):

Integrals are a sumation.

OpenStudy (anonymous):

\[ \lim_{\Delta x\to 0}\sum_{i}f(x_i)\Delta x = \int f(x)\;dx \]

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