An average of 50000 people visit zoo per day. The zoo charges $12 for admission. It is predicted that for each $1 increase the zoo would lose 1500 customers a day. Express daily revenue from ticket sales,R, as a function of the number of $1 price increases,x

Question

An average of 50000 people visit zoo per day.  The zoo charges $12 for admission.  It is predicted that for each $1 increase the zoo would lose 1500 customers a day. Express daily revenue from ticket sales,R, as a function of the number of $1 price increases,x

anonymous · Answer

Total money=50000*12
total money (with change)= (50000*12)-(1500*13)

anonymous · Answer

im mistaken, that second equation should be:

total=(50000*13)-(1500*13)

anonymous · Answer

x should represent the 1 in both the increase in revenue and price and decrease in customers

anonymous · Answer

Thank you guys...

anonymous · Answer

I'm not liking that answer though it doesn't graph right

anonymous · Answer

R(x)=(50000(12+x))-1500x(12+x)
@Oudi90    This graphs properly, missed the x after the 1500 the first time.

anonymous · Answer

maximum revenue will be realized at x=10.66 ($22.66 per ticket) revenue at $770,666.67 and attendance at 34,010 daily visitors.

anonymous · Answer

Much better thank ou ehuman