Need help with one word problem!
Joely's Tea Shop, a store that specializes in tea blends, has available 45 pounds of A grade tea and 70 pounds of B grade tea. These will be blended into 1 pound packages as follows: A breakfast blend that contains one third of a pound of A grade tea and two thirds of a pound of B grade tea and an afternoon tea that contains one half pound of A grade tea and one half pound of B grade tea. If Joely makes a profit of $1.50 on each pound of the breakfast blend and $2.00 profit on each pound of the afternoon blend, how many pounds of each blend should she make to maximize profits? What is the maximum profit?
@ganeshie8 can you help me with this last problem?
@ganeshie8 ?(:
this is a linear programming problem u have some idea about it right ?
not really..
sure ? never heard of linear programming before ? setting up a function, and maximizing it within the given linear constraints ?
i heard of it but never understood how to do it..
good :) lets do this and try to understand now
okay !
Say, she makes \(x\) packets of breakfast blend, and \(y\) packets of afternoon blend
since she gets $1.5 for each packets she sells on breakfast blend, and $2 on afternoon blend, Profit function wud be :- \(\large P = 1.5x + 2y \)
fine so far ?
okay good so far..
next see that, we dont have abundant supply of A/B grade to make these packets. so we need to make them carefully
okay
breakfast blend has a ratio of tea types, 1/3A : 2/3B afternoon blend has a ratio of tea types, 1/2A : 1/2B Also, A <= 45 and B <= 70
From above limitations, \(\large x*\frac{1}{3} + y * \frac{1}{2} \le 45\) and, \(\large x*\frac{2}{3} + y * \frac{1}{2} \le 70\)
see if that makes some sense, if it does, then we're almost done.
yea it does
first inequality above is for Grade A tea second inequaloty above is for Grade B tea
sure ?
yeep got that
okay, so here is the linear programming setup :- \(\large P = 1.5x + 2y\) constraints : \(\large x*\frac{1}{3} + y * \frac{1}{2} \le 45 \) \(\large x*\frac{2}{3} + y * \frac{1}{2} \le 70\)
okay what we suppose to do
we need to graph those constraints and find the intersection points.
we got 3 intersection points :- 1) on y axis : x=0, y=90 2) on x axis : x=105, y=0 3) when lines cross : x=75, y = 40
So, one of these points WILL GIVE THE MAXIMUM value for our Profit function.
put each point in Profit function, and see wat values u get.
how do i do that
\(P = 1.5x + 2y \) put first point, 1) on y axis : x=0, y=90
P = 180
thats right test other two points also.
2) on x axis : x=105, y=0
p = 157.5
P = 192.5
profit is less than first point, so discard 2nd point.
So, which point has greater profit ?
3rd
Yes 3) when lines cross : x=75, y = 40
Making 75 breakfast blends, and 40 afternoon blends gives her MAXIMUM PROFIT. and the maximum profit is $192.5
oh thats all i had to do?
thats all, you saying as if its simple enough to do lol :o
well no it not all simple but i thought it would be more than that lol (:
good :) always prepare for the worse.. pessimism is always good lol
jk :)
which i always do cause i always think its going to be hard lol. Thank you for your help (:
np :)
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