Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (erinweeks):

Need help with one word problem!

OpenStudy (erinweeks):

Joely's Tea Shop, a store that specializes in tea blends, has available 45 pounds of A grade tea and 70 pounds of B grade tea. These will be blended into 1 pound packages as follows: A breakfast blend that contains one third of a pound of A grade tea and two thirds of a pound of B grade tea and an afternoon tea that contains one half pound of A grade tea and one half pound of B grade tea. If Joely makes a profit of $1.50 on each pound of the breakfast blend and $2.00 profit on each pound of the afternoon blend, how many pounds of each blend should she make to maximize profits? What is the maximum profit?

OpenStudy (erinweeks):

@ganeshie8 can you help me with this last problem?

OpenStudy (erinweeks):

@ganeshie8 ?(:

ganeshie8 (ganeshie8):

this is a linear programming problem u have some idea about it right ?

OpenStudy (erinweeks):

not really..

ganeshie8 (ganeshie8):

sure ? never heard of linear programming before ? setting up a function, and maximizing it within the given linear constraints ?

OpenStudy (erinweeks):

i heard of it but never understood how to do it..

ganeshie8 (ganeshie8):

good :) lets do this and try to understand now

OpenStudy (erinweeks):

okay !

ganeshie8 (ganeshie8):

Say, she makes \(x\) packets of breakfast blend, and \(y\) packets of afternoon blend

ganeshie8 (ganeshie8):

since she gets $1.5 for each packets she sells on breakfast blend, and $2 on afternoon blend, Profit function wud be :- \(\large P = 1.5x + 2y \)

ganeshie8 (ganeshie8):

fine so far ?

OpenStudy (erinweeks):

okay good so far..

ganeshie8 (ganeshie8):

next see that, we dont have abundant supply of A/B grade to make these packets. so we need to make them carefully

OpenStudy (erinweeks):

okay

ganeshie8 (ganeshie8):

breakfast blend has a ratio of tea types, 1/3A : 2/3B afternoon blend has a ratio of tea types, 1/2A : 1/2B Also, A <= 45 and B <= 70

ganeshie8 (ganeshie8):

From above limitations, \(\large x*\frac{1}{3} + y * \frac{1}{2} \le 45\) and, \(\large x*\frac{2}{3} + y * \frac{1}{2} \le 70\)

ganeshie8 (ganeshie8):

see if that makes some sense, if it does, then we're almost done.

OpenStudy (erinweeks):

yea it does

ganeshie8 (ganeshie8):

first inequality above is for Grade A tea second inequaloty above is for Grade B tea

ganeshie8 (ganeshie8):

sure ?

OpenStudy (erinweeks):

yeep got that

ganeshie8 (ganeshie8):

okay, so here is the linear programming setup :- \(\large P = 1.5x + 2y\) constraints : \(\large x*\frac{1}{3} + y * \frac{1}{2} \le 45 \) \(\large x*\frac{2}{3} + y * \frac{1}{2} \le 70\)

OpenStudy (erinweeks):

okay what we suppose to do

ganeshie8 (ganeshie8):

we need to graph those constraints and find the intersection points.

ganeshie8 (ganeshie8):

ganeshie8 (ganeshie8):

we got 3 intersection points :- 1) on y axis : x=0, y=90 2) on x axis : x=105, y=0 3) when lines cross : x=75, y = 40

ganeshie8 (ganeshie8):

So, one of these points WILL GIVE THE MAXIMUM value for our Profit function.

ganeshie8 (ganeshie8):

put each point in Profit function, and see wat values u get.

OpenStudy (erinweeks):

how do i do that

ganeshie8 (ganeshie8):

\(P = 1.5x + 2y \) put first point, 1) on y axis : x=0, y=90

OpenStudy (erinweeks):

P = 180

ganeshie8 (ganeshie8):

thats right test other two points also.

ganeshie8 (ganeshie8):

2) on x axis : x=105, y=0

OpenStudy (erinweeks):

p = 157.5

OpenStudy (erinweeks):

P = 192.5

ganeshie8 (ganeshie8):

profit is less than first point, so discard 2nd point.

ganeshie8 (ganeshie8):

So, which point has greater profit ?

OpenStudy (erinweeks):

3rd

ganeshie8 (ganeshie8):

Yes 3) when lines cross : x=75, y = 40

ganeshie8 (ganeshie8):

Making 75 breakfast blends, and 40 afternoon blends gives her MAXIMUM PROFIT. and the maximum profit is $192.5

OpenStudy (erinweeks):

oh thats all i had to do?

ganeshie8 (ganeshie8):

thats all, you saying as if its simple enough to do lol :o

OpenStudy (erinweeks):

well no it not all simple but i thought it would be more than that lol (:

ganeshie8 (ganeshie8):

good :) always prepare for the worse.. pessimism is always good lol

ganeshie8 (ganeshie8):

jk :)

OpenStudy (erinweeks):

which i always do cause i always think its going to be hard lol. Thank you for your help (:

ganeshie8 (ganeshie8):

np :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!