34.6mL of a 0.1456M NaOH solution is used to titrate some phosphoric acid for the following unbalanced reaction below. What mass, in grams, of phosphoric acid was in the flask? Unbalanced equation: NaOH + _H3PO4 - _Na3PO4 + _H2O
Balanced is: 3NaOH + H3PO4 - Na3PO4 + 3HOH

Question

34.6mL of a 0.1456M NaOH solution is used to titrate some phosphoric acid for the following unbalanced reaction below. What mass, in grams, of phosphoric acid was in the flask? Unbalanced equation: NaOH + _H3PO4 -> _Na3PO4 + _H2O
Balanced is: 3NaOH + H3PO4 -> Na3PO4 + 3HOH

joannablackwelder · Answer

Cool, good start. Now if you convert the mL of solution into Liters, you can multiply the volume by the Molarity to get moles of NaOH. Since you are titrating, the reaction would be at the mole ration.

joannablackwelder · Answer

Then use molar mass of phosphoric acid to find grams.

joannablackwelder · Answer

*mole ratio not ration :)