Question

Given the enthalpy changes for the reaction below,

P4(s) + 6Cl2(g) --> 4PCl3(g) Delta H= -1225.6 KJ

P4(s) + 5O2(g) --> P4O10(s) Delta H= -2967.3 KJ

PCl3(g) + Cl2(g) --> PCl5(g) Delta H= -82.4 KJ

PCl3(g) + 1/2O2(g) --> Cl3PO(g) Delta H= -285.7 KJ

calculate the overall enthalpy change for the reaction P4O10 with PCl5

P4O10(s) + 6PCl5(g) --> 10Cl3PO(g) Delta H= ?