Question

What term is needed to add to each side to complete the square...

4x^ +12x =16

Answer 1

do i divide by two on the left?

Answer 2

i got 9 as an anwer is that correct??

Answer 3

@geerky42

Answer 4

Divide both sides by 4

Answer 5

wait is my answer correct?

Answer 6

@geerky42

Answer 7

First, divide both sides by 4, then take 1/2 of the coefficient of the x term, and square it. What do you get?

Answer 8

9...

Answer 9

Not 9.

Answer 10

\(\bf 4x^2 +12x =16 \quad ?\)

Answer 11

wait what do u mean by divide bothe sides? can u please show me step by step...

Answer 12

yes @jdoe0001

Answer 13

Divide both sides by 4, you get an x^2 + 3x on the left side. Take 1/2 of 3 which is 3/2. Now square 3/2, you get 9/4. So you add 9/4 to both sides!

Answer 14

\(\bf 4x^2 +12x =16\qquad \textit{let's group and common factor}\\
4(x^2 +3x) =16\qquad thus\\
4(x^2 +3x+\square^2) =16\)

Answer 15

ohhk how about this one 4x@ -20x =25 i got 25/4 is that correct>

Answer 16

im sorry the at sign is supposed to be squared

Answer 17

You are correct, add 25/4.

Answer 18

okay i have another wuestion.... it says to solve each eqation by completing the square.

x^ +6x+3=0

Answer 19

So first subtract 3 from both sides, so you get x^2 + 6x = -3

Now add 9 to both sides, so you get x^2 + 6x + 9 = - 3 + 9
(x+3)^2 = 6
(x + 3) = +/- sqrt 6
Hence, x = -3 +/- sqrt (6)

Answer 20

i dont get this question: its the same directions as the previous one...

x^ -3x-7=0

Answer 21

Add 7 to both sides.
You now get x^2 - 3x = 7
Add 9/4 to both sides, you get x^2 -3x + 9/4 = 7 + 9/4
(x - 3/2)^2 = 37/4
So, (x - 3/2) = +/- sqrt (37/4)
Hence, x = 3/2 +/- sqrt (37/4)

Answer 22

thaniks so much i have a couple of more questions.............im gonna post it on another one..