Question

find the second derivative of y=cot(3x-1)

Answer 1

y'=-csc^2(3x-1)*3
= -3csc^2(3x-1)

Then, to find y", if find it easier to put the ^2 on the outside, so
y'=[-3csc(3x-1)]^2

Now use the chain rule...
y" =2[-3csc(3x-1)] * csc(3x-1)cot(3x-1) *3

Pretty sure that's it. You can simplify if you need to.

Answer 2

@beck3295 in your second derivative, the first chain,
derivative of cosecant should give us -cosecant*cotangent.

Looks good besides that though! :)

Answer 3

Yes, it's the opposite of cscxcotx, and since it started off negative, that makes it a positive.

Answer 4

Ya but you still have the negative on the [-3csc(3x-1)] portion.
That's the negative you meant to cancel out with the new one right? :o

Answer 5

Oh did I miss one somewhere? :D lol

Answer 6

See how wolfram changed the arguments from (3x-1) to (1-3x)'s? That's suspicious....
I'm trying to figure out what's going on here -_-

Answer 7

Yep, I noticed that! ...that's what I'm looking at, too. Ugh. Gotta figure this out!

Answer 8

Yeah, if we just move the negative all the way to the outside on y', then you're right. When WA turned those around, they took out another negative, which means there should be a third one in there. Yup. I missed it. Thanks!

Answer 9

Bahh that darn wolf :P lol

Answer 10

I know! And I didn't even look at their answer until you said something. I hate some of the stuff they do. Why can't they just leave it alone!