CaCO3+2HCL---CaCl2+CO2 +H2O

a)What is the maximum volume of carbondioxide at stp that can be obtaied by the complete reaction of 3.0 mol HCL with excess Caco3?

b)What mass of CaCO3 is required to EXACTLY react with 150 cm^3 of 2.0M HCL?

C)How many cm^3 of 1.5 HCL are required to react with excess Ca CO3 to produce 5.6 dm^3 of carbondioxide gas at STP?

Question

CaCO3+2HCL--->CaCl2+CO2 +H2O

a)What is the maximum volume of carbondioxide at stp that can be obtaied by the complete reaction of 3.0 mol HCL with excess Caco3?



b)What mass of CaCO3 is required to EXACTLY react with 150 cm^3 of 2.0M HCL?

C)How many cm^3 of 1.5 HCL are required to react with excess Ca CO3 to produce 5.6 dm^3 of carbondioxide gas at STP?

anonymous · Answer

@abb0t  here it is

abb0t · Answer

Well, where are you struggling? Balancing?

anonymous · Answer

with figuring out how to start the question .its hard for me to know where to start i can balace

anonymous · Answer

i know stp is 22.4 and thats the co2

anonymous · Answer

can i use the formula vol=molar vol x #of moles?

abb0t · Answer

The qeustion is already balanced. Yes. 1 mole at STP = 22.4 L

abb0t · Answer

Use conversion to convert from $\sf \color{}{\frac{22.4~L}{mol}}$

anonymous · Answer

i got 7.46

anonymous · Answer

i found the mass of caco3 and i got 100g

anonymous · Answer

should i do 100x7.46?

anonymous · Answer

hey @abb0t  is this correct?