Question

CaCO3+2HCL--->CaCl2+CO2 +H2O

a)What is the maximum volume of carbondioxide at stp that can be obtaied by the complete reaction of 3.0 mol HCL with excess Caco3?



b)What mass of CaCO3 is required to EXACTLY react with 150 cm^3 of 2.0M HCL?

C)How many cm^3 of 1.5 HCL are required to react with excess Ca CO3 to produce 5.6 dm^3 of carbondioxide gas at STP?

Answer 1

@wolfe8

Answer 2

Which one are you talking about?

Answer 3

ok 4 a i got 7.46/100 is it right

Answer 4

22.4/3.0=7.46 i got 100g of caco3

Answer 5

7,46x100 i meant

Answer 6

Since you have 3 mol and that is equal to 2 parts, for 1 part of CO2 you will do 3/2 x STP I think

Answer 7

ok

Answer 8

For b you use the same approach, but find the number of moles of HCL first

Answer 9

so 4 the first one it is incorrect how i started it off a?

Answer 10

I actually don't understand what you did...

Answer 11

ok i got 22.4(stp) divided by the 3.0 mol

Answer 12

What? Why are you doing that?

Answer 13

i found the molar mass then of caco3 and got 100g

Answer 14

since they asked what is the maximum volume

Answer 15

I am so confused. You don't need to fine any molar mass for a. You just need the number of moles. And you are given that for 2 parts of HCL. So you divide by 2 to find for 1 part since there is only 1 part of CO2 produced.

Answer 16

oh ok anyways thanks for your help i havent slept all day my brain needs to rest .thanks again

Answer 17

You're welcome. Do you get it though?

Answer 18

Is that 1.5 M HCl?

Answer 19

yes

Answer 20

5.6 L CO2*(1 mol CO2/22.4 L)*(2 mol HCl/1 mol CO2)*(1 L HCl/1.5 mol HCl)*(1000 mL/1L)=mL HCl needed.

Answer 21

Write it all out and let me know if you have questions.

Answer 22

kk