Question

Given log 3=0.4471, log 5=0.699, log7=0.8451, log2=0.3010, find the value of

Answer 1

\[\log \frac{ \sqrt[3]{245} }{ 315 }\]

Answer 2

@terenzreignz

Answer 3

Oooh...
Prime factorisation lang katapat niyan.

at wag maarte, pang grade-3 yun

Answer 4

\[\Large \frac{\sqrt[3]{245}}{315}= \frac{\sqrt[3]{5\cdot 7^2}}{3^2\cdot 5\cdot 7}\]

Answer 5

nag sosolve sa papel eh, -____-

Answer 6

bagal eh :P

Answer 7

nawawala pen ko ehh

Answer 8

wtf

Answer 9

binigay ko nga sayo eh

Answer 10

at hindi basta basta nakaka cancel
nakalilimutan mo yata...
\[\Large \sqrt[3]{abc}= a^\frac13b^\frac13c^\frac13\]

Answer 11

aiyt,,, ahahah

Answer 12

ano sunod?

Answer 13

Well, duh...\[\Large \log\left(\frac{\sqrt[3]{245}}{315}\right)= \log\left(\frac{\sqrt[3]{5\cdot 7^2}}{3^2\cdot 5\cdot 7}\right)\]

I mean, geez, do I have to do everything? XD

Answer 14

yup, xDD

Answer 15

\[\log \frac{ \sqrt[3]{245} }{315 }=\log \left( 245 \right)^{\frac{ 1 }{ 3 }}-\log315\]
\[=\frac{ 1 }{ 3 }\log \left( 5*7^{2} \right)-\log \left( 5*7*3^{2} \right)\]
\[=\frac{ 1 }{ 3 }\log 5+\frac{ 2 }{3 }\log7-\log 5-\log7-2\log3\]
\[=-\frac{ 2 }{3 }\log5-\frac{ 1 }{3 }\log7-2\log 3\]
sbstitute the values and get the solution.

Answer 16

Not forgetting, of course, that
\[\Large \log(\sqrt[3]M) = \log(M^\frac13) = \frac13\log(M) \]

Answer 17

ahah,xD

Answer 18

yeah,, i understand it now, xDD

Answer 19

The rest is up to you.... I'm sure you can do this :P
If not, make a bloody peanut-butter sandwich and try again... it seems to be the solution to everything :D

Answer 20

\[\frac{ 1 }{ 3 }\log(5.7)-\log(3^2.5.7)\]

Answer 21

T_T

Answer 22

<whitling sounds...>
\[\huge \frac{ 1 }{ 3 }\log(5.7^{\color{red}2 })-\log(3^2.5.7)\]

Answer 23

sorry,, didn't noticed that

Answer 24

I'm sure :P

Confident with logs now?