Question

CD=3 BE=x and AF=x+2 find lengths BE and AF

Answer 1

@agent0smith

Answer 2

ik I have to find x but idk how I had and idea but it was wrong

Answer 3

first put all the info on there

Answer 4

got that dones already

Answer 5

AF=X+2
=BE+2
=CD+2+2
=3+2+2=7
BE=7-2=5
AF=7

Answer 6

so how do I find x.
I had x+2+x=3 but that was wrong lol

Answer 7

@RadEn

Answer 8

hmmm can you post a quick screenshot of the picture?

Answer 9

suree give me a sec

Answer 10

The middle line is the average of the other two... so add them and divide by 2

(3 + x+2)/2 = x

Answer 11

If i recall correctly

Answer 12

AB=BC
FE=ED
Hence 2 BE=AF+CD
2x=x+2+3
x=5
BE=5
AF=5+2=7

Answer 13

ok.... look like a trapezoid to me then... parallel sides or BASES are atop and bottom

so

so we could say that our bases are CD and AF and noticing the tickmarks, so all 4 sides are equal, so we could say that BE is our MIDSEGMENT, so keeping in mind that a \(\bf \textit{MidSegment of a Trapezoid} = \cfrac{1}{2}\times (base1 + base2)\\ \quad \\
x = \cfrac{1}{2}(3 + (x + 2))\implies x = \cfrac{5+x}{2}\)

solve for "x" to get BE

Answer 14

ok I think I got it thanks to all :)

Answer 15

yw

Answer 16

can u help with another on for this question?

Answer 17

ok

Answer 18

if m angle c =117 deg find m angle a and m angel d hint use thm 3.3 and thm 8.14

Answer 19

so.... you have a picture of it I gather :)

Answer 20

its for the same pic

Answer 21

hhmmm I get that... dunno what "thm" stand for though

Answer 22

theorem

Answer 23

either way is easy anyhow

Answer 24

oklol

Answer 25

CD and AF are just 2 parallel lines, thus the BASES of the trapezoid
the lines connecting, CA and DF, are equal in length, and thus will make equal angles atop and equal angles at the bottom