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find the zeros of 2t^4+3t^3+16t-24
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\[ 16t-24=8(2t+3) \]And \[ 2t^4+3t^3=t^3(2t+3) \]
So factoring gets you\[ (t^3+8)(2t+3) \]
This is how you approach these problems. Finding the \(0\)s for the factors should not be hard.
\[ 2t+3=0 \]And \[ t^3+8=0 \]
but you have to make the \[t^3 +8 \] = something so would you just end up with 2 as the answer for that one?
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wait it would be -2
Yeah
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