Please help... Need answers! Will Fan! In the below system, solve for y in the first equation. 2x + y = 11 5x - 2y = -1 AND What is the value of y in the solution to the following system of equations? 5x - 3y = -3 2x - 6y = -6 Please Help!
Do you know the reduction or substitution methods?
For example, in the case of substitution you can solve the first equation for y \[y=11-2x\]And substitute this into the second equation, \[5x-2(11-2x)=-1\] And solve for x.
The same can be applied to the second system of equations you posted.
I know of nether methods. I am so lost.
Can you solve the system in the form I left to you?
5x−2(11−2x)=−1?
Also, here are the answer choices: question 1: 2x + 11 -2x + 11 2x - 11 -2x - 11 question 2: -1 zero 1 2
Well, XD I think I gave you the answer in the first post. \[y=-2x+11\]
For question 2, you should solve the system by the substitution method.
Although it is easier if you use reduction.
I would rewrite the second system after divide by 2 the second equation, 5x - 3y = -3 x - 3y = -3 And then I would solve for x in the second, x=-3+3y And substitute in the first, 5(-3+3y)-3y=-3 And solve for y.
Do you understand it?
It seems that y=1, but better try to find the solution by yourself.
Ok, I am just having trouble with the first equation now. I got 1 for the 2nd problem, correct?
@John_es
Sorry, I was out. Yes, you was correct.
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