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Mathematics 19 Online
OpenStudy (anonymous):

6/5a + 5/3a+2

OpenStudy (anonymous):

solving for a?

OpenStudy (anonymous):

no. it says: perform the indicated operations

OpenStudy (anonymous):

\[\frac{ 6 }{ 5a } + \frac{ 5 }{ 3a } + 2\]

OpenStudy (anonymous):

like that?

OpenStudy (anonymous):

the "+2" goes with the -->3a. so it will be 3a+2 the rest of the equation is fine

OpenStudy (anonymous):

ok, so how do you add two fractions?

OpenStudy (anonymous):

wel for instance the top numbers 6 and 5 you add them and the bottom i believe you multiply each to equal 15. im not sure

OpenStudy (anonymous):

in order to add two fractions you need to have common denominators

OpenStudy (anonymous):

so would the common denominator be 15?

OpenStudy (anonymous):

\[\frac{ 6 }{ 5a }+\frac{ 5 }{ 3a+2 }=\frac{ 6(3a+2) }{ 5a(3a+2) }+\frac{ 5(5a) }{ (3a+2)5a }\]

OpenStudy (anonymous):

so the common denominator is 5a(3a+2)

OpenStudy (anonymous):

basically cross multiplying is being done?

OpenStudy (anonymous):

yep, I like to think that I'm multiplying the numerator by whatever is missing from the denominator.

OpenStudy (anonymous):

so the problem isn't done but do you think you got it from here?

OpenStudy (anonymous):

i think i do. well i try to finish the problem and i got 6+5/5a(3a+2) which equals 11/5a(3a+2) . Am I right or wrong?

OpenStudy (anonymous):

i cross out the common numbers from the denominator to the numerator

OpenStudy (anonymous):

\[\frac{ 6(3a+2) }{ 5a(3a+2) }+\frac{ 5(5a) }{ (3a+2)(5a) }=\frac{ 18a+12 }{ 5a(3a+2)}+\frac{ 25a }{ 5a(3a+2) }\]

OpenStudy (anonymous):

that's the next step

OpenStudy (anonymous):

then since you have a common denominator just rewrite it as a single fraction with that common denominator and combine the terms in the numerator

OpenStudy (anonymous):

some instructor may want you to multiply the denominator but it doesn't change anything

OpenStudy (anonymous):

thank you so much ! you were a great help.

OpenStudy (anonymous):

no problem, glad to help

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