Question

Can I get a little help with this? f(-1)=4 f'(-1)=7
Let h(x)=(x^6)f(x). Evaluate h'(x) at x=-1

Answer 1

By the Chain and Product Rule:
h'(x) = (x^6)(f'(x)) + (6x^5)(f(x))
So, h'(-1) = ((-1)^6)(f'(-1)) + (-6)(f(-1)
= (1)(7) + (-6)(4)
= 7-24
= -17

Answer 2

....ohhh. Thanks again!

Answer 3

welcome.