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Mathematics 24 Online
OpenStudy (anonymous):

How do I find the zeros of this polynomial function? f(x)=x^3-2x^2+x

OpenStudy (anonymous):

factor them

OpenStudy (anonymous):

x(x^2 - 2x + 1) = x(x-1)(x-1) set each factor equal to zero, you get x = 0 and x = 1

OpenStudy (anonymous):

Wouldn't that make both of them x=1 since they are both (x-1)

OpenStudy (tkhunny):

x = 0, x = 1, and x = 1 -- Yes.

OpenStudy (anonymous):

Thanks

OpenStudy (tkhunny):

It is more often expressed with the work "multiplicity" x = 0 x = 1 with multiplicity 2

OpenStudy (anonymous):

So x=0 has a multiplicity of 1 and x=1 has a multiplicity of 2 since there are two "(x-1)"?

OpenStudy (tkhunny):

I think you have it. Good work. It's not usually necessary to state the Multiplicity of 1. That is normally understood. No harm in mentioning it, though.

OpenStudy (anonymous):

Okay, thanks!

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