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How do I find the zeros of this polynomial function? f(x)=x^3-2x^2+x
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factor them
x(x^2 - 2x + 1) = x(x-1)(x-1) set each factor equal to zero, you get x = 0 and x = 1
Wouldn't that make both of them x=1 since they are both (x-1)
x = 0, x = 1, and x = 1 -- Yes.
Thanks
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It is more often expressed with the work "multiplicity" x = 0 x = 1 with multiplicity 2
So x=0 has a multiplicity of 1 and x=1 has a multiplicity of 2 since there are two "(x-1)"?
I think you have it. Good work. It's not usually necessary to state the Multiplicity of 1. That is normally understood. No harm in mentioning it, though.
Okay, thanks!
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