Question

find the value of the constant (c) that makes the function continuous.

f(x)={x^2-c for x < 5
{4x+2c for x ≥ 5

Answer 1

I think something like this should work, solve for c:
\[\lim_{x \rightarrow 5} x^2 - c = 4(5) + 2c\]

Answer 2

I figured it out actually.

\[x ^{2}-c=4x+2c\] when x =5,

so the answer is \[c=\frac{ 5 }{ 3 }\]

Answer 3

but yeah thats the same thing as what you gave pretty much.