Assume that all variables are nonzero Simplify 119x exponent24/7x exponent8
I got 119/7x exponent16
\( \dfrac{119x^24}{7x^8} \) Can you divide 119 by 7? what do you get? For the x part, use this rule. You got it correct. \( \dfrac{a^m}{a^n} = a^{m - n} \) Also, use the symbol ^ (shift 6) for exponent. x^8 means x to the 8 power.
I tried to do that on the computer couldnt get it ,But I got my answer correct
Assume that all variables are nonzero 28r^6s^7t^9/7r^3s^7t^6
For the first problem, did you divide 119 by 7?
\( \dfrac{28r^6s^7t^9}{7r^3s^7t^6} \) \( = \dfrac{28}{7} \times \dfrac{r^6}{r^3} \times \dfrac{s^7}{s^7} \times \dfrac{t^9}{t^6} \) Divide the numbers in the first fraction. For all the fractions with variables, apply the rule above where you subtract the exponents. What do you get?
4=10/10
What? 10/10 = 1, which is not equal to 4. What do you mean?
Help me with this ...But back to the question it stated that assuming all the variable are zero
All variable are NONzero.
\(= \dfrac{28}{7} \times \dfrac{r^6}{r^3} \times \dfrac{s^7}{s^7} \times \dfrac{t^9}{t^6}\) \( = 4 \times r^3 \times s^0 \times t^3\) \(= 4r^3t^3\)
y\[y^{?}/y ^{8}=y ^{9} Find the Missing Exponent \]
\( \dfrac{y^?}{y^8} = y^9\) Apply the rule of division of powers: \( y^{? - 8} = y^9\) What number minus 8 equals 9?
? - 8 = 9 Add 8 to both sides: ? = 17
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