Question

This is just a random Math question see if you can answer it dont use any search engines to help find it.

what is a number that can be divided by 3 and have a reminder of 1 , the same number and divided 4 reminder of 1 , same number divided by 5 and reminder of 1 , same number and divided by 6 and reminder of 1 , same number and divided by 7 and reminder of 1?

Answer 1

This is a challenge.

Answer 2

Do you mean remainder?

Answer 3

Yes sorry.

Answer 4

k just use the chinese remainder theorem

Answer 5

No I know the answer its Kinda like a brain teaser.

Answer 6

I want to see if anyone else can get the answer right.

Answer 7

oh ok give me a minute

Answer 8

Everyone Please try to do it.

Answer 9

Plenty could be that number. 7! + 1 comes to mind

Answer 10

You could just get the least common multiple of 3,4,5,6, and 7, and then add 1.

Answer 11

Ok so whats the answer its just one number.

Answer 12

421 rather.

Answer 13

1926

Answer 14

wait no thats not right

Answer 15

wtong both but 1926 is really close.

Answer 16

who wants the answer.

Answer 17

How is 421 wrong?
Does it fail any of the criterion?

Answer 18

just a bit heres the number i got 841

Answer 19

Actually wait yes 421 would be right.

Answer 20

Of course that would also work.
420 is a the LCM of 3,4,5,6,7 and would leave a zero remainder when divided by any of those, so if you add 1, it will leave a remainder of 1.

840 is twice 420, and is therefore, a multiple of 3,4,5,6, and 7, and would leave a zero remainder when divided by any of those. Add 1 to it, you fit the criteria.

yeesh XD

Answer 21

So your got it right and explained it good job again just a little brain teaser.

Answer 22

^_^

Answer 23

Thank you all who tried it.

Answer 24

I like \(1 (mod~ 420)\) =)