Question

Limit question?

Answer 1

rationalize the numerator!

Answer 2

know how to ?

Answer 3

Yes, conjugate ?

Answer 4

okay you can use L'hospital rule here...

Answer 5

that would be fairly easy..

Answer 6

if you can use L'Hopitals , yes, easy
if you cannot , yes, multiply and divide by conjugate \sqrt (5x^2-1) +2

Answer 7

@prince90p Don't assume they know that rule.

Answer 8

@wio okie got that.! then as hartnn said multiply numerator and denominator by conjuagte...

conjugate is \[\sqrt{5x^2-1} +2\]

Answer 9

Okay, ive done that. I get
5x2+4/
(x-1)[sqrt(5x2-1)+2]

Answer 10

check you answer it should have been

\[5x^2-5/(x-1)(\sqrt{5x^2-1}+2)\]

Answer 11

we have just used

\[(a+b) (a-b)=a^2-b^2\]

Answer 12

(5x^2-1) - 2^2

Answer 13

Alrightt I understand from this point onward! Thank you all:)

Answer 14

you are welcome bro..! :)

Answer 15

good help @prince90p :)
keep up the good work :)

Answer 16

@hartnn thanks bro,! :)