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Chemistry 15 Online
OpenStudy (anonymous):

Someone please help ! I will ensure that u get 2-3 medals (by posting a random "question" on chem openstudy, and awarding u with best answer)

OpenStudy (anonymous):

OpenStudy (anonymous):

on lap pg back"Data Processing", how is is possible to know moles of kmno4?

OpenStudy (anonymous):

i know its volume

OpenStudy (aaronq):

lol i don't think anyone really cares about medals. Did you do a titration of Fe(III) with KMnO4?

OpenStudy (anonymous):

yes basically

OpenStudy (anonymous):

i posted pictures (front and back) if that will help.

OpenStudy (aaronq):

so write an equation for the reaction. Solve for moles like you would with any stoichiometric problem.

OpenStudy (anonymous):

well, thats what i had done

OpenStudy (anonymous):

sorry for the delay, my internet connection was soo poor i had to switch computers

OpenStudy (aaronq):

thats alright, i think it was he site. You did which?

OpenStudy (anonymous):

i wrote the balanced reaction (2) (refer to front page of lab) using half reaction method. how would this help me? im ultimately trying to find concentration of kmno4, but what is the purpose of finding kmno4?? ah confusing! thanks in advance

OpenStudy (aaronq):

is your ultimate goal is to find moles of Fe(III)?

OpenStudy (anonymous):

no moles of Fe III so as to connect it to the first equation..

OpenStudy (anonymous):

@aaronq sorry but this is really urgent..

OpenStudy (anonymous):

am i making sense?

OpenStudy (anonymous):

since this is redox (first equation) u use the moles of Fe(iii) and moles of NH3OH+ to find molar ratio of NH3OH+ to Fe (iii). this tells us how many electrons NH3OH+ released so we can find possible oxidation product Z

OpenStudy (aaronq):

so if you know the moles of KMnO4, you can use stoichiometry to find the moles of Fe(III) produced (through oxidation of Fe(II) which originated from the reduction reaction with the amine compound). So, have you found the moles of Fe(III)?

OpenStudy (aaronq):

okay, so you do understand whats going on

OpenStudy (anonymous):

yes its just that i dont really know how to find moles of kmno4 if i only know the volumes!

OpenStudy (aaronq):

In part 1 you standardized the KMNO4 solution, meaning you figured out it's molarity

OpenStudy (anonymous):

not really. i dont really understand that procedure either..how would i go about finding the molarity? I used moles of Fe2+ to find moles of kmnO4 but i think thats incorrect

OpenStudy (anonymous):

with reference to my balanced reaction of my second equation. I found the molar ratio (in 2nd equation) of Fe 2+ to MNO4 to be 5:1

OpenStudy (anonymous):

which is right. i checked with my chem teacher.

OpenStudy (aaronq):

Are you talking about the titration in part 1?

OpenStudy (anonymous):

yes. is that the incorrect appproach?

OpenStudy (aaronq):

no that's fine. So you know the molarity of the Fe(II) containing solution (it tells you in the procedure) use that molarity to find the moles present in the sample (volume) and find the moles of KMnO4 that result from the titration (since you know the volume you used).

OpenStudy (aaronq):

i have to go to class, sorry. :S good luck !

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