Add or subtract. Simplify by collecting like radical terms if possible. 3√162- √200+ 7√50 Answer was 52√2 Need an idea how they got there
First, in order to simplify the square roots, you need to find the prime factors of 162, 200, and 50. Do you know how to find the prime factors of a number?
9*18 for 162, 50*4 for 200, 25*2 for 50?
Those products are correct, but they are not the full prime factorizations. Here they are: 162 = 2 * 3 * 3 * 3 * 3 200 = 2 * 2 * 2 * 5 * 5 50 = 2 * 5 * 5
I see, what would i do next?
Alright I get to that point so far
Since we are dealing with square roots, we need factors that come in multiples of 2. \(3\sqrt{162} - \sqrt{200} + 7\sqrt{50}\) \(3 \sqrt{2 \times 3^4} - \sqrt{2^2 \times 2 \times 5^2 } + 7\sqrt{2 \times 5^2}\) \(3 \sqrt{2} \times \sqrt{3^4} - \sqrt{2^2} \times \sqrt{2} \times \sqrt{5^2 } + 7\sqrt{2} \times \sqrt{5^2}\) \(3 \sqrt{2} \times \color{red}{\sqrt{81}} - \color{red}{\sqrt{4}} \times \sqrt{2} \times \color{red}{\sqrt{25 }} + 7\sqrt{2} \times \color{red}{\sqrt{25}}\) Now you see which square roots can be simplified.
Now we take the square roots of 25, 81, and 4.
\(9 \times 3\sqrt{2} - 2 \times 5 \times \sqrt{2} + 5 \times 7\sqrt{2} \)
\(27\sqrt{2} - 10 \times \sqrt{2} + 35\sqrt{2} \)
Now we the terms: \(52 \sqrt{2} \)
Ah I see thanks
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