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Mathematics 13 Online
OpenStudy (anonymous):

A study of three hundred teenagers found that the number of hours they spend on instant messaging sites each week is normally distributed with a mean of 13 hours. The population standard deviation is 5 hours. What is the margin of error for a 99% confidence interval? 0.745 0.334 0.320 0.413 I think it is the second one.

OpenStudy (anonymous):

@phi Save me a gain

OpenStudy (anonymous):

if im incorrect what is the formula im supposed to be plugging into?

OpenStudy (anonymous):

@shamil98

OpenStudy (anonymous):

@Jamierox4ev3r

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

Yeah Shamil's here

OpenStudy (shamil98):

To be honest with you, I do not know how to approach this question, sorry.

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

I know that the margin of error in the mean is calculated as \[error_{s} = \frac{s}{\sqrt{N}}\] Where s is the standard deviation and N is the total sample size.

OpenStudy (anonymous):

|dw:1382153359762:dw|

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