find dx/dt of xy=4. when x=1 and dy/dt=-6
@KeelyLynn ready?
yes
Show me how far you've got with this problem.
\[dx \div dt= 4 div y\] \[=4y ^{-1}=-4y ^{-2}dx \div dt\]
then i insert the given numbers for y & dy/dt and i dont get the right answer
sorry that last dx/dt is suppose to be dy/dt
No. Remember that you are differentiating all variables with respect to time.
OK, so what you did is first rewrite xy = 4 as\[y =\frac{ 4 }{ x }\]Correct? This is fine. Remember that the product rule is another option.
I'm sorry, I meant, you rewrote the function as
\[x =\frac{ 4 }{ y }\]
yes
OK that's fine. Then after differentiation, you obtained\[\frac{ dx }{ dt }=\frac{ -4 }{ y ^{2} }\frac{ dy }{ dt }\]This is correct.
What do you think you should do next?
i moved the y^2 to the top making y^-2
i mean moved the y to the top making y^-1
oh i see what you did. moved the y^-2 after differeiation to the bottom to make it positive
i just realized it gives me find dx/dt when x=1..but theres no x?
Yes. Look! You're given x = 1 and dy/dt = -6. What you need to find is dx/dt but you don't know y. How will you find the value of y? That is an important question here.
im not sure
@KeelyLynn please think about it. You need the value for y to solve for dx/dt. How will you do that. Hint: Use the given equation.
Substitute x = 1 into the original equation, and solve for y.
isolate y? and plug in the given value for x. to find y
so y=4
Yes!
Now find dx/dt. What is the solution?
3/2
Perfect. I knew you could do it! Excellent work!!
@KeelyLynn do you have a better understanding of these problems, now?
yes thank you!
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