Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is 28 square meters.
The side of the retangle measure ? Meters

Question

Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is 28 square meters.
The side of the retangle measure  ? Meters

campbell_st · Answer

so you have for the perimeter where length = l and width = w

22 = 2l + 2w    or  11 = l + w

and for area 

28 = lw

take the perimeter equation and make w the subject and substitute into the area equation...

then solve for l... 

when you get l, substitute into either equation to find w

yttrium · Answer

We know that LW = 28 and 2(L+W) = 22
You can actually solve this using substitution, considering LW = 28
L = 28/W
Therefore, considering 2(L+W) = 22
$$2(\frac{ 28 }{ w}+w) = 22$$
Therefore, upon simplifying you now solve for W.
And to solve for L (just use the equation L = 28/W
And that's it! :D

anonymous · Answer

Thank you both