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Mathematics 16 Online
OpenStudy (anonymous):

If cscx=3, 90 degrees

OpenStudy (yttrium):

Where you get stucked?

OpenStudy (anonymous):

The fact that I'm working with csc and that's (x/2), so I don't understand the problem

OpenStudy (yttrium):

But can you solve the sinx, cosx,and tanx of this?

OpenStudy (yttrium):

When you already solved that, that is the time you can solve for the problem itself using half-angle identities. :) Do you know it?

OpenStudy (anonymous):

Yeah I just have trouble starting it

OpenStudy (yttrium):

Let's get started. \[cscx = \frac{ hyp }{opp } = \frac{ 3 }{ 1 }\] Therefore, hypotenuse is equal to 3 and the side opposite is equal to 1. So, by pythagorean theorem you can solve the 3rd side. Using pythagorean theorem, we can solve the the adj side So what is the value of the 3rd side?.

OpenStudy (anonymous):

2sqrt(2)

OpenStudy (yttrium):

I think it would be better if you @dnova21 will join me solving so you can as well visualise what's happening during solving. :))

OpenStudy (anonymous):

|dw:1382164602788:dw| now find cos x and tanx and find sinx/2 and others

OpenStudy (anonymous):

so if I found that cscx=2sqrt(2) then I can just follow what Harindu mentioned ?

OpenStudy (yttrium):

No.cscx = 3 and not 2sqrt2. 2sqrt2 is actually the value of our adjacent side. Actually it is -2sqrt(2) since the problem tells us that is is found on the 2nd quadrant.

OpenStudy (anonymous):

Oh okay

OpenStudy (anonymous):

lol since sinx and cosx between 90 and 180 are postive and cos and tangen are negative

OpenStudy (yttrium):

So, given the triangle |dw:1382166441051:dw| What are the sinx, cosx and tanx of our angle? @Harindu , we actually used here the coordinate plane as well. Such angle found bet 90 and 180 are found in quadrant two and hence all values of x must be negative.

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