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Mathematics 16 Online
OpenStudy (anonymous):

Find the length of the midsegment. The diagram is not to scale.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Mimi_x3

OpenStudy (anonymous):

@CGGURUMANJUNATH

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

@dan815

Directrix (directrix):

The segment joining the midpoints of two sides of a triangle has measure 1/2 that of the third side. So, you have a little Algebra to do: 6x + 2 = (1/2)*(4x + 36) 2* (6x + 2) = 4x + 36 ---> Solve for x @DeeBush96

OpenStudy (anonymous):

do i compare like terms first

Directrix (directrix):

There are no like terms to compare just yet.

Directrix (directrix):

Use the Distributive Property to multiply the 2 times the quantity 6x + 2 2* (6x + 2) = 4x + 36 12x + 4 = 4x + 36 --> Can you solve for x from this point?

OpenStudy (anonymous):

8x= 32

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

Yes, and x = 4. But, you have to get the length of the midsegment. So, evaluate 6x + 2 for x = 4.

OpenStudy (anonymous):

6(4)+2= 24+2=26

Directrix (directrix):

Correct.

OpenStudy (anonymous):

@Directrix Which statement is not necessarily true? Given: DE is the ⊥ bisector of JL

OpenStudy (cggurumanjunath):

?

OpenStudy (anonymous):

@CGGURUMANJUNATH do u need the answer choices

OpenStudy (cggurumanjunath):

yes.

OpenStudy (cggurumanjunath):

do you have them with you ?

OpenStudy (cggurumanjunath):

post the answer choices .

OpenStudy (cggurumanjunath):

@DeeBush96

OpenStudy (anonymous):

ok hold on

OpenStudy (cggurumanjunath):

k

OpenStudy (anonymous):

OpenStudy (anonymous):

@CGGURUMANJUNATH

Directrix (directrix):

DeeBush96 The answer options are upside-down. Here they are right side up, I think.

OpenStudy (cggurumanjunath):

3rd and 4th statement are not necessarily true

Directrix (directrix):

This --> DE is the ⊥ bisector of JL means that segment DE is perpendicular to segment JL AND that segment DE cuts segment JL in half giving JK = KL.

Directrix (directrix):

It is true that DJ = DL because all points on the perpendicular bisector of a segment are equidistant from the endpoints of the segment.

OpenStudy (anonymous):

@Directrix yes i think they are congruent

OpenStudy (anonymous):

i thinks its c DL=LE

Directrix (directrix):

To say that DL = LE is incorrect because we do not know that segment LJ is the perpendicular bisector of segment DE.

OpenStudy (anonymous):

SO DL = LE is true

Directrix (directrix):

Which statement is not necessarily true? Segment DL ≅ Segment LE

Directrix (directrix):

@DeeBush96 For what reason do you think that this statement is true: >>>SO DL = LE is true

Directrix (directrix):

The confusion stems from the drawing making it appear that those segments are congruent. That is why the theorems are needed.

OpenStudy (anonymous):

because its both in the same position so that y i thought it will be true but we are looking for what is not that true

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

See attachment.

Directrix (directrix):

The question is yours to which to submit an answer. So, if you think another option is correct, then go with that. If it were my test, I would submit as the answer DL = LE is not necessarily correct. It is not guaranteed true. It may be but it does not have to be. The other three options must be true because of the given information in the problem.

OpenStudy (cggurumanjunath):

dj=dl is true because of sas(side angle side ) property of 2 triangles dkj and dkl; hence dl is not equal to le; dl=le is not necessarily true 3rd statement are not necessarily true

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