Question

What are the Solutions ?
1/2x^2+2x+3 = 0

Please show me step by step, not just the answer

Thank you.

Answer 1

@Yttrium

Answer 2

\[\frac{ 1 }{ 2 }x^2 + 2x+3 = 0\]
right?

Answer 3

right (:

Answer 4

I will be here to check the answer xD

Answer 5

Lol Okay Lola (x

Answer 6

XD

Answer 7

what grade is this? :O

Answer 8

Least common denominator ^_^

Answer 9

You better get rid of the fraction first. And that is by multiplying the whole equation by the LCD. (Our LCD is 2, know why?)

Answer 10

So it could be easier to work out ?

Answer 11

@lola honors Algebra 2

Answer 12

wow :O so timaa, ur older den meh o-o well derp O_O

Answer 13

Hence.
\[2[\frac{1 }{ 2 }x^2+2x+3 = 0]\]
\[x^2+4x+6 = 0\]
Just factor them out to get the zeroes.
And I think this is unfactorable.

Answer 14

*sits in a corner and thinks* .-.

Answer 15

yes @timaashorty

Answer 16

There are none. Your Discriminant, b² - 4ac is -2, so D < 0

If you'd use that in the formula \\[\frac{ -b \pm \sqrt{D}\ }{ 2 }\]

it would give: \\[\frac{ -2 \pm \sqrt{-2}\ }{ 2 }\] you'd run into an error because you cannot use the root of a negative factor :)

Answer 17

Or you can work with getting rid of the 1/2 first to make it easier ;)

Answer 18

So let's continue.
If that is the case, you can use the quadratic formula to get the zeroes.
Quadratic formula is:
\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
Where the equation must be in the form of ax^2+bx+c = 0

Answer 19

Our equation \[x^2+4x+6 = 0\] is already in the form of ax^2+bx+c = 0
Hence,
\[\frac{ -4\pm \sqrt{4^2-4(1)(6)} }{ 2(1) }\]
Our zeros therefore are:
\[\frac{ -4\pm \sqrt{-8} }{ 2 }\]
\[\frac{ -4\pm 8i }{ 2 }\]
\[-2\pm4i\] --> Final answer.

Answer 20

THANK YOU VERRRYY VERRY MUCH! xD @mieel & Yttruim (: I apreciate Your help(:

Answer 21

And yes Char, I think I am Older, lol How old are you ? (i4got)