Question

Suppose an automobile has a kinetic energy
of 2600 J.
When it moves with two times the speed,
what will be its kinetic energy?
Answer in units of J

Answer 1

\(KE = \frac{1}{2} mv^2\)

Answer 2

when v becomes 2v :-

\(KE_{new} = \frac{1}{2} m(2v)^2\)

\(~~~~~~ = 4 \times \frac{1}{2} mv^2\)

\(~~~~~~ = 4 \times KE\)

Answer 3

thank you :)

Answer 4

np :)